Pb+2 C2H3O2-1 <---- these are the ions and their charges
Pb+2 C2H3O2-1 C2H3O2-1 <---- the charges have to add up to zero, so two -1 acetate ions cancel out one +2 lead ion
Pb(C2H3O2)2 <---- simplify
*** Note that acetate can either be represented by C2H3O2 or CH3COO
When yeast consume and metabolize sugar, they produce ethanol and carbon dioxide, CO2. (Incidentally, when human beings metabolize sugars, we also produce CO2. The difference is, we exhale it.)
The density of ethanol is 0.789 g/cm3, or 0.789 kg per liter.
There are 3.7854 liters per gallon, so 1 gallon of ethanol weighs 2.987 kg.
There are 2.2046 lbs per kilogram, so 1 gallon of ethanol weighs 6.584 lbs.
Compare that with the weight of 1 gallon of water: 8.3454 lbs
No. read the ingredients on th label.
To find this answer it is necessary to first find the chemical formula of aluminum sulfate utilizing the valence charges from the periodic table. Aluminum Sulfate is a molecular formed by the ionic bonding of aluminum to to the polyatomic ion of sulfate
Al = +3
SO4 is a polyatomic ion with a charge of -2
Therefore after balancing the equation, you get the chemical formula
Next, in order to find osmolarity, you must first find molarity. This is done by converting grams to moles.
Moles are calculated in grams/Liter and is equal to the molecular weight. What is the molecular weight of aluminum sulfate. Looking at the periodic table, you sum the atomic weights of each element, shown in AMUs.
Al = 27 (x2) = 54
S = 32 (x3) =96
O = 16 (x12) = 192
We add these up to determine the molecular weight of the substance, which can be used to determine the molarity of this solution.
MW = 342g, which means that one mole of aluminum sulfate is 342 grams per liter of water. We can now use the information presented in the above problem to determine molarity
10 grams dissolved in 200 ml of water.
Since measurements are in grams per liter, we can assume that if 10 grams were dissolved in 200 ml of water, then 50 grams will dissolve in 1000 ml, or 50 grams per liter (multiply both factors by five).
We must use our grams of solute to convert grams into our molarity
50 g x 1 mole/342 grams of aluminum sulfate to determine the molarity.
= .15 M
At this point, to determine osmolarity, you must be aware that osmolarity is the measure of PARTICLES within a solution per liter. Realizing that aluminum sulfate is held together by an ionic bond, it will freely dissolve in water and produce Al ions and SO4 ions.
So we sum the particles of each:
2 Al ions per molecule
3 SO4 ions per molecule
Therefore, multiplying the molarity of the aluminum sulfate solution times 5 (total 5 particles from each molecule) will give you the osmolarity.
= 0.73 Osm per liter of aqueous solution.